Suppose voltage v is applied across a resistance r. The power dissipated in the resistance is p. Now the same voltage v is applied across a parallel combination of three equal resistors each of resistance r. Then the power dissipated in the second case will be a. P b. 3p c. P/3 d. 2p/ 3
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P=VI. I=V/R
P=V^2/R
1/Rp = 3/R
Rp =R/3
so I think answer is= B
P=V^2/R
1/Rp = 3/R
Rp =R/3
so I think answer is= B
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