Question

Suppose we draw circles with each side of AABC as diameter find out whether the third corner of the triangle is inside,on or outside the circle,​

Answer 1

Given: In ΔABC, ∠A = 60° and ∠B = 70°

Using angle sum property:

∠A + ∠B + ∠C = 180°

⇒ 60° + 70° + ∠C = 180°

⇒ 130° + ∠C = 180°

⇒ ∠C = 180° − 130°

= 50°

We know that angle in a semi circle is a right angle.

If AB is the diametre of the circle then ∠C should be equal to 90°.

However, here ∠C is less than 90°. Therefore, vertex C will lie outside the circle.

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