Suppose we had a blank 4-sided die and a blank 8-sided die. How many different sums can we have and still have a fair game (each sum has the same probability of showing up
Answers
Given : 4-sided die and 8-sided die.
To Find : How many different sums can we have
each sum has the same probability of showing up
Solution:
Dice 4 sided { 1 ,2 , 3 4 }
Dice 8 Side { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 }
Possible out comes = 4 * 8 = 32
Possible sums = { 2 , 3 ,4 , 5 ,6 , 7 , 8 , 9 , 10 , 11 , 12 }
SUM f possible case
2 1 ( 1, 1)
3 2 ( 1 , 2) , ( 2 , 1)
4 3 ( 1, 3) , ( 2 , 2) , ( 3 , 1)
5 4 ( 1, 4) , ( 2 , 3) , ( 3 , 2) , ( 4 , 1)
6 4 ( 1 , 5 ) , ( 2 , 4) , ( 3 , 3) , ( 4 , 2)
7 4 ( 1 , 6 ) , ( 2 , 5) , ( 3 , 4) , ( 4 , 3)
8 4 ( 1 , 7 ) , ( 2 , 6) , ( 3 , 5) , ( 4 , 4)
9 4 ( 1 , 8 ) , ( 2 , 7) , ( 3 , 6) , ( 4 , 5)
10 3 (2, 8) , ( 3 , 7) , ( 4 , 6)
11 2 (3 , 8) ( 4, 7)
12 1 ( 4, 8)
Sum 5 , 6 , 7 , 8 , 9 has same probability = 4/32 = 1/8
Sum 2 and 12 has same probability = 1/32
Sum 3 and 11 has same probability = 2/32 = 1/16
Sum 4 and 10 has same probability = 3/32
Learn More:
if two dice are tossed, find the probability of throwing a total of 10 or ...
brainly.in/question/7714685
a pair of dice thrown. find the probability of getting a sum of 10 or ...
brainly.in/question/7850369
A pair of fair-dice is rolled. What is the probability that the second die ...
brainly.in/question/9514304