Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second card are colored black, and one side of the third card is colored red and the other side is colored black. The 3 cards are mixed up in a hat, and 1 card is randomly selected and put down on the ground. If the upper side of the chosen card is colored red, what is the probability that the other side is colored black?
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Answer:
sorry I don't have no answer
Given : 3 cards identical in form except that both sides of the first card are colored red, both sides of the second card are colored black, and one side of the third card is colored red and the other side is colored black
The 3 cards are mixed up in a hat, and 1 card is randomly selected and put down on the ground.
the upper side of the chosen card is colored red
To Find : probability that the other side is colored black
Solution:
RR BB RB
Probability of getting R card up
= (1/3) .1 + (1/3) (1/2)
= 1/3 + 1/6
= 1/2
Probability of getting R card up = 1/3 when red both sides ( other side = Red)
Probability of getting R card up = 1/6 when red one side and black other side ( other side = black)
upper side of the chosen card is colored red,
Hence probability that the other side is colored black = (1/6) /( 1/2)
= 2/6
= 1/3
1/3 is the probability that the other side is colored black
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