Question

suppose we have a box with 3red,2black,5whiteballs each a ball drawn in 3 returned to the box.what is the probability of drawing ? ​

Answer 1

Answer:

To solve this question, We have to use Bayes Theorem to get reverse probability.

Let first ball drawn is red and second ball drawn is white.

Probability of choosing a box at random =31.

probabilty of drawing a red ball from box−1=p(R∣B1)=31

probabilty of drawing a red ball from box−2=p(R∣B2)=21

probabilty of drawing a red ball from box−3=(R∣B3)=61 

 probability of getting the ball from box−2 if red ball is selected is given by

P(B2∣R)=P(B1)×p(R∣B1)+P(B2)×p(R∣B2)+P(B3)×p(R∣B3)P(B2)×p(R∣B2)

=31×31+31×21+3

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