Question

suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer. if it begins to desend from 15m above the ground what will be its position after 45minuts

Answer 1

Acceleration due to gravity=-10m/s^2 (round of)
Height from the grounf=15m
Total Time =45 minutes=2700s
Initial velocity=0m/s
Using formula s=ut+1/2at^2
s=0×2700 +1/2×(-10)×2700× 2700
s=-36,450,000m
This is total distance
Current position= -36,450,000+15=-36,449,985