Suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer, then answer the following:(i) An elevator descends into a mine shaft at the rate of 5 metre per minute. What will be its position after one hour?(ii) If it begins to descend from 15 m above the ground, what will be its position after 45 minutes?
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Since downwards is negative, the velocity of the elevator is -5 m/min.
(i) Displacement = Velocity x Time = -5 m/min x 60 min = -300 m.
(ii) Displacement from initial position = Velocity x Time = -5 m/min x 45 min = -225 m.
However, since we started 15 m above ground, displacement from the ground level = -225 + 15 m = -210 m.
Answered by
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Answer:
Since downwards is negative, the velocity of the elevator is -5 m/min.
(i) Displacement = Velocity x Time = -5 m/min x 60 min = -300 m.
(ii) Displacement from initial position = Velocity x Time = -5 m/min x 45 min = -225 m.
However, since we started 15 m above ground, displacement from the ground level = -225 + 15 m = -210 m.
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