suppose we represent the distance moved up by a positive integer and distance moved down by negative integer then Answer the following a. a submarine goes vertically down in the water at a speed of 4m/Min what will be it's position after 1 hour b. if the submarine begin s to come up from depth of 58m what will be it's position after 12 minutes if it is moving at the speed of 3m/min
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Answered by
5
Answer:
a,.position is at -240 m
b. position is at -22 m
Answered by
34
Speed of Submarine=4m/min
No of minutes in one hour=60 minutes
Therefore, Distance vertically covered by the submarine=4*60=240m
Also, as the distance covered downwards is expressed with a negative integer, answer to A= -240m
That means it will be 240 m below water
Now, Speed of Submarine moving upwards=3m/min
Distance covered by it in 12 minutes=3*12=36m
Now, the current distance=58m below water
Distance below water is to be expressed with a negative integer
So, the current distance below water will be -58m
After 12 min the distance will be=-58+36=-22m
As the distance is in negative, it means that the submarine will be 22m below water after 12min
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