Math, asked by qwerty2338, 4 months ago

Suppose we take three non-zero numbers:— a, b and c, such that,
a+b = c.
Then, (a+b)² = c².
=> a²+b²+2ab = c². — Equation (i).
But, according to Pythagoras theorem,
a²+b² = c². — Equation (ii).
From equations (i) and (ii),
a²+b²+2ab = a²+b².
=> 2ab = 0.
=> ab = 0/2 = 0. — Equation (iii).
But, equation (iii) is not possible, since a and b are non-zero.
Which is correct then?
Is c² = a²+b²+2ab, or is c² = a²+b² ???​

Answers

Answered by morer9403
0

Answer:

what is your question......

Answered by bhattisandeep65
1

Answer:

both can be correct in different cases as Pythagoras is only applied in right angle triangle

hope it help

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