Question

suppose we throw a dice 4 times in a row. what is the expected number of outcomes 1 in these throws?

Answer 1

Answer:

Step-by-step explanation:

4/24

Answer 2

Answer:

Number of outcome=4, Probability=1/6

Step-by-step explanation:

Concept= Probability

Given= The rolling of dice four times and getting one as outcome

To find= The probability of getting 1

Explanation=

We have been in the question that suppose we throw a dice 4 times in a row. What is the expected number of outcomes 1 in these throws?

We know that a dice is rolled once the outcome can be : 1,2,3,4,5,6 only

Since we are throwing the dice four times in a row that means the same outcome is coming 4 times when a single dice is rolled.

The outcome of 1 dice is 6.

The outcome of Four dice rolled in a row will be 4*6 =24.

So the outcome of 1 can come in each dice 1 time , therefore in a throw of  four dice in row the outcome 1 can come 4 times also.

The number of favorable outcome is 4 .( 1,1,1,1)

Probability=Number of favorable outcome/total number of outcome

Probability of getting 1= 4/24 = 1/6

Therefore the expected outcome of 1 is 4 and the probability is 1/6.

#SPJ2