suppose we throw a die once what is the probability of getting a number greater than 3
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Answered by
3
the probability is 1/2
MichaelJackson13:
nthg aak fast
Answered by
5
Hey frnd here is ur answer.
Let s={1,2,3,4,5,6}
n(s)=6.
Let A be the event of getting a number greater than 3.
A={4,5,6}
n(A)=3
p(A)=n(A)/n(S)
=3/6
=1/2
=0.5
hope it helps u:-)
Let s={1,2,3,4,5,6}
n(s)=6.
Let A be the event of getting a number greater than 3.
A={4,5,6}
n(A)=3
p(A)=n(A)/n(S)
=3/6
=1/2
=0.5
hope it helps u:-)
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