Question

Suppose X is normally distributed with mean 5. If P(X $ 3) = 0.2 what is the
standard deviation of X
1 point
o = 0.42
Ο Ο Ο
o = -0.42
0 = 0.38
O o = 2.38​

Answer 1

Answer:

deviation, variance, quartile deviation gives the dispersion of the data. Therefore the odd one is mean.

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Answer 2

Answer:

The standard deviation of X for P(X $ 3) = 0.2 is 2.3809

Step-by-step explanation:

• Normal distribution is a probability distribution having a bell shape and symmetry around the mean.
• The normal distribution is converted into standard normal distribution to ease the process of detemination of the probability.
• The value of z in standard normaldistribution is given by

       $z=\frac{x-mean}{\sigma}$

       where $\sigma$ is the stabdard deviation.

Step 1 of 1:

• The random variable is 3
• Probability of the distribution is 0.2
• Mean of the distribution is 5
• From the probability distributio table, z value corresponding to 0.2 probability is -0.84
• The z valueis calculated as

        $z=\frac{x-mean}{\sigma}$

        $-0.84=\frac{3-5}{\sigma}\\-0.84=\frac{-2}{\sigma}\\\\\sigma= 2.3809$