Question

Suppose x is the smallest integer greater than 3 such that when it is divided by 6 or 8, the remainder is 3. y is the smallest integer greater than 2 such that when it is divided by 6 or 8, the remainder is 2. What is x-y? (a) 1 (b) 2 (c) 3 (d) 4​

Answer 1

Answer:

(a) 1.

Step-by-step explanation:

The lowest common multiple of 6 and 8 is 24.

So x = 24 +3 = 27.

By the same reasoning y = 24 + 2 = 26.

Thus x - y = 27-26 = 1.