Question

suppose X:Y=7:11 and X:(Y+2)=3:5. what is the value of X?​

Answer 1

Step-by-step explanation:

x/y=7/11

11x=7y

11x-7y=0 ------(1)

x/y+2=3/5

5x=3(y+2)

5x=3y+6

5x-3y=6 -------(2)

multiply eq(1) by 3 and eq(2) by 7,

eq(1) becomes 33x-21y=0 -----(3)

eq(2) becomes 35x-21y=42 -----(4)

Subtracting (3) from (4),

2x=42

x=21

from (1), 11x21-7y=0

231=7y

y=33

Pls mark as brainliest!!!

Answer 2

Answer:

x=21

Step-by-step explanation:

x/y = 7/11

x = 7y/11 (1)

x/(y+2) = 3/5

x= 3(y+2)/5

x = 3y/5 + 6/5

x - 3y/5 = 6/5 (2)

by substituting the values

7y/11 -3y/5 =6/5

(35y -33y)/55 = 6/5

2y/55 = 6/5

2y = 6×55/5

2y = 11×6

y= 66/2

=33

NOW,

x= 7y/11

=7×33/11

=21ans