Question

suppose x,y,z are positive integers such that 6x+2^x+y +2^y=1780 then xy+yz+xz=​

Answer 1

Answer:

step 1

y=6/x

z=10/x

step 2

substitute 6/x for y and 10/x for z in the third equation

(6/x)(10/x)=15

60/x^2=15

x^2=60/15

x^2=4

x=2

step3

substitute for the value of x in the first two equations to find the value of y and z

2y=6 y=3

2z=10 z=5

The answer is x=2, y=3, z=5

If you are looking for the multiplication of xyz then the answer would be 2*3*5=30