Question

Suppose x²+y²=123xy then prove that 2log(x+y)=3log5+logx+logy​

Answer 1

Answer:

x²+y²=123xy

add 2xy on b. s.

x²+y²+2xy=125xy

(x+y) ²=125xy

apply log on b. s.

log(x+y) ²=log 125xy

log a^m=m log a

so,

2 log(x+y) =log(5³*x*y)

2 log(x+y) =3log(5) +log x+ log y

Answer 2

Step-by-step explanation:

Answer...................