suppose y varies jointly with x and y , if y=24 when x=6 and z=2 , find y when x=18 and z=36
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Answer:
If
y
varies jointly as
x
and
z
, we can write this as
y
=
k
x
z
where
k
is the constant of proportionality (we'll be finding this)
In the situation, we're given that
y
=
6
when
x
=
4
and
z
=
2
, so let's plug those in:
6
=
k
(
4
)
(
2
)
k
=
3
4
Now that we know the proportionality constant (which stays the same), we can use it in solving for
y
when
x
is
6
and
z
=
8
:
y
=
(
3
4
)
(
6
)
(
8
)
=
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
36
∣
∣
−−−−−−−−
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