Math, asked by zhericklogan18, 2 months ago

suppose y varies jointly with x and y , if y=24 when x=6 and z=2 , find y when x=18 and z=36

Answers

Answered by shreyaju
0

Answer:

If

y

varies jointly as

x

and

z

, we can write this as

y

=

k

x

z

where

k

is the constant of proportionality (we'll be finding this)

In the situation, we're given that

y

=

6

when

x

=

4

and

z

=

2

, so let's plug those in:

6

=

k

(

4

)

(

2

)

k

=

3

4

Now that we know the proportionality constant (which stays the same), we can use it in solving for

y

when

x

is

6

and

z

=

8

:

y

=

(

3

4

)

(

6

)

(

8

)

=

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

36

−−−−−−−−

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