suppose you are given three resistances of values 2,4,6 ohms which the following value is not possible to get by arranging resistances in various combinations
1. less than 2
2. 4.4
3. 7.33
4. 6.75
Answers
Answer: option 4) 6.75 is not possible
Step-by-step explanation:
We are given three resistances of 2, 4 & 6 ohms.
Required formulas
When in series connections:
Net R = R1+R2+R3
When in parallel connections:
Net R = 1/R1 + 1/R2 + 1/R3
Now, we will calculate the net resistance in each of the cases formed from the combinations of 3 resistances, by arranging them in different arrangements of series, parallel and series-parallel connections as shown in the figure below:
Case 1: referring to the image in combination 1
Net Resistance, R = 2+4+6 = 12 ohms
Case 2: referring to the image in combination 2
Net Resistance, 1/R = ½ + ¼ + 1/6 = (6+3+2)/12 = 11/12
⇒ R = 1.09 ohms
Case 3: referring to the image in combination 3
Net Resistance, R = 4/3 + 6 = (4+18)/3 = 7.33 ohms
Case 4: referring to the image in combination 4
Net Resistance, R = 2 + 12/5 = (10+12)/5 = 4.4 ohms
Case 5: referring to the image in combination 5
Net Resistance, R = 1.5 + 4 = 5.5 ohms
Case 6: referring to the image in combination 6
Net Resistance, 1/R = 1/8 + 1/6 = 7/24
⇒ R = 24/7 = 3.42 ohms
Case 7: referring to the image in combination 7
Net Resistance, 1/R = 1/10 + 1/2 = 6/10
⇒ R = 10/6 = 1.66 ohms
Case 8: referring to the image in combination 8
Net Resistance, 1/R = 1/12 + 1/4 = 1/3
⇒ R = 3 ohms
Thus, from above 8 cases it is clearly seen that option 4. 6.75 ohm is not possible in any of the cases of combinations of 3 resistances.
Step-by-step explanation:
heyy ya
same as above
but see no need to d o this big just try the easy combinatuons