Math, asked by Swaaryin, 1 year ago

suppose you are given three resistances of values 2,4,6 ohms which the following value is not possible to get by arranging resistances in various combinations


1. less than 2
2. 4.4
3. 7.33
4. 6.75​

Answers

Answered by bhagyashreechowdhury
22

Answer: option 4) 6.75 is not possible

Step-by-step explanation:

We are given three resistances of 2, 4 & 6 ohms.

Required formulas

When in series connections:

Net R = R1+R2+R3

When in parallel connections:

Net R = 1/R1 + 1/R2 + 1/R3

Now, we will calculate the net resistance in each of the cases formed from the combinations of 3 resistances, by arranging them in different arrangements of series, parallel and series-parallel connections as shown in the figure below:

Case 1: referring to the image in combination 1

Net Resistance, R = 2+4+6 = 12 ohms

Case 2: referring to the image in combination 2

Net Resistance, 1/R = ½ + ¼ + 1/6 = (6+3+2)/12 = 11/12

⇒ R = 1.09 ohms

Case 3: referring to the image in combination 3

Net Resistance, R = 4/3 + 6 = (4+18)/3 = 7.33  ohms

Case 4: referring to the image in combination 4

Net Resistance, R = 2 + 12/5 = (10+12)/5 = 4.4  ohms

Case 5: referring to the image in combination 5

Net Resistance, R = 1.5 + 4 = 5.5  ohms

Case 6: referring to the image in combination 6

Net Resistance, 1/R = 1/8 + 1/6 = 7/24

⇒ R = 24/7 = 3.42 ohms

Case 7: referring to the image in combination 7

Net Resistance, 1/R = 1/10 + 1/2 = 6/10

⇒ R = 10/6 = 1.66 ohms

Case 8: referring to the image in combination 8

Net Resistance, 1/R = 1/12 + 1/4 = 1/3

⇒ R = 3 ohms

Thus, from above 8 cases it is clearly seen that option 4. 6.75 ohm is not possible in any of the cases of combinations of 3 resistances.

Attachments:
Answered by jayshreegadhari
0

Step-by-step explanation:

heyy ya

same as above

but see no need to d o this big just try the easy combinatuons

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