Suppose you are selling two different kinds of magazine for a certain school
fund-raiser. You keep track of your sales for one week, and at the end of the week
you have the following numbers: Monday: 6 fashion magazines and 2 sports
magazines, Tuesday: 6 fashion magazines and 3 sports magazines, Wednesday: 8
fashion magazines and 5 sports magazines, Thursday: 6 fashion magazines and 3
fashion magazines, Friday: 2 fashion magazines and 4 sports magazines, Saturday:
3 fashion magazines and 1 sports magazine, and Sunday: 2 fashion magazines and
1 sports magazine.
Answers
Answer:
At least 1' questions are best done by finding the complement i.e. I find the probability of selecting no fashion magazine and subtract that from 1 to get the probability of selecting at least 1 fashion magazine.
So I ask myself, what is the probability of selecting 3 sports magazines?
Since 4 of the 8 are sports magazines, probability of picking a sports mag is 1/2.
Probability of picking a second sports mag becomes 3/7. (because only 3 are left)
Probability of picking a third sports mag becomes 2/6. (Now only 2 sports mags are left)
Hence probability of picking 3 sports mags = 1/2 x 3/7 x 2x6 = 1/14
Then, probability of picking at least one fashion magazine will be 1 - 1/14 = 13/14
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