Suppose you are shooting an arrow from the top of a building at an height of 6 metre to a target on the ground at an angle of depression of 60°. What is the distance between you and the object ?
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Answered by
113
Hey mate !!
Here's the answer !!
Refer to the attachment for the diagram.
Let AB be the building you are standing. So AB = 6 m
And let Angle of Depression = ∠ C.
=> ∠ C = 60°
To find The distance between you and the object.
So According to the Diagram, the distance between you and the object is AC, which is the hypotenuse.
So Sin Ф = Opposite / Hypotenuse
Sin 60° = 6 m / Hypotenuse
=> √ 3 / 2 = 6 / Hypotenuse
=> Hypotenuse = 6 * 2 / √ 3
=> Hypotenuse = 12 / √ 3
=> Hypotenuse = 12 √ 3 / 3
=> Hypotenuse = 4 √ 3 m
Hence distance between the target and building is 4 √ 3 m.
Hope my answer helped !!
Cheers !!
Here's the answer !!
Refer to the attachment for the diagram.
Let AB be the building you are standing. So AB = 6 m
And let Angle of Depression = ∠ C.
=> ∠ C = 60°
To find The distance between you and the object.
So According to the Diagram, the distance between you and the object is AC, which is the hypotenuse.
So Sin Ф = Opposite / Hypotenuse
Sin 60° = 6 m / Hypotenuse
=> √ 3 / 2 = 6 / Hypotenuse
=> Hypotenuse = 6 * 2 / √ 3
=> Hypotenuse = 12 / √ 3
=> Hypotenuse = 12 √ 3 / 3
=> Hypotenuse = 4 √ 3 m
Hence distance between the target and building is 4 √ 3 m.
Hope my answer helped !!
Cheers !!
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HPMakers30:
thnx so much bro
Answered by
12
height of building =6m
hypotenuse(distance b/w you and the object)=?
angle of depression=60°
sin60=heigh of building÷distance b/w you and object
root 3÷2=6÷x
root3×x=12
x=12÷root3
x=4root3
.
. .distance between you and object is 4 root 3 meters
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