Suppose you are standing on a tall ladder. If your distance from the centre of the ears is 2R. what will be your weight?
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Answer:
R is the radius of earth . Hence, acceleration will be 1/4th times of acceleration at Earth's surface. Hence , weight of body at 2R distance from centre of earth will be 1/4th of weight of body at Earth's surface
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Answer:
1/4th
Explanation:
We know formula of Acceleration due to gravity at h height from the Earth's surface is given by g = g₀/(1 + h/R)²
Here, g₀ is the acceleration due to gravity on Earth's surface.
h is the height from the Earth's surface.
R is the radius of earth .
A/C to question,
My distance from the centre of earth is 2R
So, my distance from the surface of earth is 2R - R = R
∴ g = g₀/( 1 + 1/1)² = g₀/(2)² = g₀/4
Hence, acceleration will be 1/4th times of acceleration at Earth's surface.
Hence , weight of body at 2R distance from centre of earth will be 1/4th of weight of body at Earth's surface.
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