Suppose you drop a die at random find the probability of getting (1) 2 (2) a number (3) anumber less than 3
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Total no. of oucomes= 6
P(E)= No. of outcomes Favourable to event/ Total no. of outcomes.
1. P(of getting 2)= 1/6
2. P(of getting a number)= 6/6=1
3. P(of getting a no. less than 3)= 2/6= 1/3.
I hope this will help you dear...
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