Math, asked by sriharsha9054, 7 months ago

Suppose you drop a die at random on the rectangular region shown in the figure. What is the probability that it will land inside the circle with diameter 1 m?

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Answered by Anonymous
29

\Large\frak{\underline{\underline{Question:}}}

Suppose you drop a die at random on the rectangular region shown in figure.What is the probability that it will land inside the circle with diameter 1m?

\Large\frak{\underline{\underline{Answer:}}}

\underline{\bigstar\:\textsf{Area \: of \: rectangle:}}

\normalsize\dashrightarrow\sf\ Area \: of \: rectangle = length \times\ breadth \\\\ \normalsize\dashrightarrow\sf\ Area = 3 \times\ 2\\\\ \normalsize\dashrightarrow\sf\  Area = 6 \\\\ \normalsize\dashrightarrow\sf\ Area = \bf\ 6m^2\\\\\\\underline{\bigstar\:\textsf{Area \: of \: circle:}} \\\\\normalsize\dashrightarrow\sf\ Area \: of \: circle = \pi r^2 \\\\ \normalsize\dashrightarrow\sf\ Area = \pi \times\ r \times\ r \\\\ \normalsize\dashrightarrow\sf\  Area = \pi \times\ \frac{1}{2} \times\ \frac{1}{2} \\\\ \normalsize\dashrightarrow\sf\ Area = \frac{\pi}{4}\\\\ \normalsize\dashrightarrow\sf\ Area = \bf\frac{\pi}{4} m^2

 \rule{120}{2}

\underline{\textsf{Probability \: of \: Event:}}

\star Event : Chances of die will land under circle.

\normalsize\ : \implies\sf\ P(E) = \frac{No. \: of \: possible \: outcomes}{No. \:  of \: total \: outcomes}\\\\\\\normalsize\ : \implies\sf\ P(die) = \frac{Area \: of \: circle}{Area \: of \: rectangle}\\\\\\\normalsize\ : \implies\sf\ P(die) = \frac{\frac{\pi}{4}}{6}\\\\\\\normalsize\ : \implies\sf\ P(die) = \frac{\pi}{24}\\\\\\\normalsize\ : \implies{\underline{\boxed{\sf \red{ P(die) = \frac{\pi}{24} }}}}

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Anonymous: Good!
Answered by Anonymous
14

\huge\underline\mathrm{SOLUTION:-}

AnswEr:

  • Probability is \mathsf { \frac{\pi}{24} }.

Need To Find:

  • We use area to find probability = ?

ExPlanation:

Here:

  • Diameter of circle = 1m
  • Radius of circle = 1/2 m

Now,

  • Area of rectangle = Length × Breadth

Putting the values according to the given formula:

➠ Area of rectangle = 3 × 2

➠ Area of rectangle = 6

  • Hence, the area of rectangle is 6 .

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And,

  • Area of circle = πr²

Putting the values according to the given formula:

➠ Area of circle = \mathsf {\pi\bigg(\frac{1}{2}\bigg)^2}

➠ Area of circle = \mathsf {\pi  \times  \frac{1}{4} m {}^{2} }

  • Hence, the area of circle is \mathsf {\pi  \times  \frac{1}{4} m {}^{2} } .

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Now,

  • P (die will land inside circle)

\mathsf {\frac{Area\:of\: circle}{Total\:Area}}

\mathsf {  \frac{\pi \times  \frac{1}{4} }{6} }

\mathsf { \frac{\pi}{6 \times 4}}

\mathsf { \frac{\pi}{24} }

  • So, Probability is \mathsf { \frac{\pi}{24} }.

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