Question

suppose you have 12000 to invest some amount at rate of 10%and the rest at 15%how sjould you invest each rate yeald 12% on total amount invested​

Answer 1

Answer:

Let the time be 1 year.

Let the time be 1 year.For r=12%

Let the time be 1 year.For r=12%A=P+(100P×r×t)

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.Then,

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.Then,12000=[x+(100x×10×1)]+[(12000−x)+(100(12000−x)×15×1)]

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.Then,12000=[x+(100x×10×1)]+[(12000−x)+(100(12000−x)×15×1)]Solving for x we get,

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.Then,12000=[x+(100x×10×1)]+[(12000−x)+(100(12000−x)×15×1)]Solving for x we get,x=7,200

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.Then,12000=[x+(100x×10×1)]+[(12000−x)+(100(12000−x)×15×1)]Solving for x we get,x=7,200⟹12000−7200=4,800

Let the time be 1 year.For r=12%A=P+(100P×r×t)A=12000+(10012000×12×1)⟹A=Rs.13,440Let Rs.x be invested with 12% rate.Then,12000=[x+(100x×10×1)]+[(12000−x)+(100(12000−x)×15×1)]Solving for x we get,x=7,200⟹12000−7200=4,800Hence,Rs.7200 is invested at rate 10% and Rs.4,800 at rate 15%.

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Answer 2

Answer:

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Step-by-step explanation:

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