Question

Suppose you have 600.0 grams of room temperature water (20.0 degrees Celsius) in a thermos. You drop 90.0 grams of ice at 0.00 degrees Celsius into the thermos and shut the lid. (a) What is the equilibrium temperature of the system?

Answer 1

Explanation:

(a) since, heat is the energy that flows from the high temperature to the low temperature. So the heat which was lost by the water is grained by the ice.

so heat which has lost=mcΔT

=600gm*1cal/gm.C*

=12000cal

Again for the ice to melt the heat gained by the ice is=m*L(f)

=90gm*80Cal/gm

=7200Cal

so the equilibrium temperature will be

(b) Since, we know that the heat which the water has lost will be equal to the mass of ice*latent heat of freezing of the ice

12000cal=m1*80Cal/gm

m1=150gm.

so the mass of the ice which remained is=150-150=0gm.

hope this helps.....