Suppose you have a 64 gigabyte flash storage system, with a 4096 byte page size. How big would the flash translation table be, assuming each page has a 32 bit address, and the table is stored as an array? Marks: 2 MCQ a) 32 megabytes b) 32 bytes c) 64 bytes d) 64 megabytes
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d)64 mb
as 64gb/4k=16page addresses and as each address requires 4 bytes the answer would be 16*4=64mb
as 64gb/4k=16page addresses and as each address requires 4 bytes the answer would be 16*4=64mb
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Each address requires 32 bits, or 4 bytes.
The array size would therefore be 16MB*4=64MB.