Computer Science, asked by EAGUKARTHIK8341, 1 year ago

Suppose you have a 64 gigabyte flash storage system, with a 4096 byte page size. How big would the flash translation table be, assuming each page has a 32 bit address, and the table is stored as an array? Marks: 2 MCQ a) 32 megabytes b) 32 bytes c) 64 bytes d) 64 megabytes

Answers

Answered by deathstrokee15
0
d)64 mb
 as 64gb/4k=16page addresses and as each address requires 4 bytes the answer would be 16*4=64mb



chandanmac2phoenix: 64GB/4K=16MB page addresses.
Each address requires 32 bits, or 4 bytes.
The array size would therefore be 16MB*4=64MB.
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