Question

Suppose you have a gas in a container being pressed down by a piston. The initial volume of the gas is 5.0 m3 and the pressure is 7.5 mmHg. If the volume decreases to 4.0 m3what is the pressure? (The product of the volume and pressure remain constant.)5.0 m37.5 mmHg) = (P)(4.0 m3

Answer 1

Answer:

Since PV = Constant , the question become extremely easy.

Explanation:

PV = Constant

P1 V1 = P2 V2

7.5 * 5 = P2 x 4

P2 =  9.375

Feel free to ask if any doubt.

Answer 2

The pressure is 9.4 mm Hg

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$     (At constant temperature and number of moles)

$P_1V_1=P_2V_2$  (At constant temperature and number of moles)

where,

$P_1$ = initial pressure of gas = 7.5 mm Hg

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = $5.0m^3$

$V_2$ = final volume of gas = $4.0m^3$

$7.5\times 5.0=P_2\times 4.0$  

$P_2=9.4mmHg$

The pressure is 9.4 mm Hg

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