Question

Suppose you have been given this classful IP address 130.1.1.8.
a. You want to create a network of 1024 (assignable) IP addresses, what will be the length of network and host part?
b. Write down the subnet mask for this IP address
c. Write down the Network ID for this network along with prefix length
d. Write down the broadcast IP address in this network
e. How many additional (extra) IP addresses do you have in this network? (Whereas the requirement is 1024 IP addresses as mentioned above)

Answer 1

Explanation:

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Answer 2

Answer:

Explanation:

A)  Class B addresses are for medium to large sized networks. Class B allows for 16,384 networks by using the first two octets for the network ID. The first two bits in the first octet are always 1 0. The remaining six bits, together with the second octet, complete the network ID. The 16 bits in the third and fourth octet represent host ID and allows for approximately 65,000 hosts per network. Class B network number values begin at 128 and end at 191.

Public IP Range: 128.0.0.0 to 191.255.0.0

So there would be 4094 hosts

B) The subnet mask for 130.1.1.8 is 255.255.255.0

C) Network ID is 130.1.0.0

D) broadcast Ip is 130.1.225.225

E)   3070

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