Question

suppose you walk from a point A to B 40m due west and then B to C 30m due north . find the distance and the displacement​

Answer 1

Total distance walked from A to C is 40+30m = 70m
Displacement = srqt(40*40 + 30*30) = 50m

Answer 2

Displacement will be equal to 50 m and distance will be equal to 70 m

Explanation:

We have given that you walk from point A to point B 40 m due to west

And then 30 m due to north

As west and north is 90° apart from each other

Let the distance traveled in west direction $D_1=40m$

Distance traveled in north direction $D_2=30m$

Angle between both distance is 90°

So displacement will be equal to $D=\sqrt{D_1^2+D_2^2+2D_1D_2cos\Theta }=\sqrt{30^2+40^2+2\times 30\times 40\times cos\Theta }=\sqrt{30^2+40^2+0}=50m$

Distance will be equal to 40+30 = 70 m

A man goes 10m due east and then 30m due north. Find the distance from the starting points.​

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