Question

suppose your weight on the surface of the Earth is 600N the height equal to the radius of the Earth then, what will be your weight there?​

Answer 1

We have my weight on Earth as 600N (too heavy bro).

Where we have taken g as 10m/s^2.

(Me weight my chosen acceleration and to make calculations easy but the following steps will work the same on 9.80 or 9.81 m/s^2 whatever you prefer)

So mass × g = 600N.

My mass = 60 Kg in this case.

As g is given by,
$\frac{GM}{{r}^{2} } = 10$

Where r is the distance of object from the center and M is the mass of the body and G is too famous to explain,

Now since you have doubled my distance from the center,
the the value of g must change to,
$\frac{GM}{ {(2r)}^{2} } \\ \\ = \frac{GM}{4 {r}^{2} } \\ \\ = \frac{GM}{ {r}^{2} } \times \frac{1}{4} \\ \\ = 10 \times \frac{1}{4}\frac{m}{ {s}^{2} } \\ \\ = \frac{5}{2} \frac{m}{ {s}^{2} } \\ \\ = 2.5 \frac{m}{ {s}^{2} }$


So my weight should become,

60× 2.5 N

= 150N


o_0
I'm not heavy the height I'm living on is wrong.