Physics, asked by guddu3434, 11 months ago

suppose your weight on the surface of the Earth is 600N the height equal to the radius of the Earth then, what will be your weight there?​

Answers

Answered by allysia
6
We have my weight on Earth as 600N (too heavy bro).

Where we have taken g as 10m/s^2.

(Me weight my chosen acceleration and to make calculations easy but the following steps will work the same on 9.80 or 9.81 m/s^2 whatever you prefer)

So mass × g = 600N.

My mass = 60 Kg in this case.

As g is given by,
  \frac{GM}{{r}^{2} }  = 10 \\

Where r is the distance of object from the center and M is the mass of the body and G is too famous to explain,

Now since you have doubled my distance from the center,
the the value of g must change to,
 \frac{GM}{ {(2r)}^{2} }  \\  \\  =  \frac{GM}{4 {r}^{2} }  \\ \\   =   \frac{GM}{ {r}^{2} } \times  \frac{1}{4}   \\  \\  = 10 \times  \frac{1}{4}\frac{m}{ {s}^{2} }   \\  \\  =  \frac{5}{2}  \frac{m}{ {s}^{2} } \\  \\  = 2.5 \frac{m}{ {s}^{2} }


So my weight should become,

60× 2.5 N

= 150N


o_0
I'm not heavy the height I'm living on is wrong.
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