Question

Supposing the ionization energy of hydrogen atom is 640ev. point out the main shell having energy equal to -40ev



The ans. Is (n=4)

Answer 1

Answer: -

If the ionisation energy of the Hydrogen atom is 640eV. the n = 4 main shell having energy equal to 40eV.

Explanation: -

For hydrogen atom, Z = 1.

Energy for nth main shell of hydrogen atom = Ionization Energy of Hydrogen atom / n²

40 = 640/ n²

n² = 640/40

n = 4

Thus, if the ionisation energy of the Hydrogen atom is 640eV. the n = 4 main shell having energy equal to 40eV.

Answer 2

It depends upon number of shell as they increases so the ionic energy also increases