Question

Suqare shaped tiles of side 40cm are to be fix in a hall of dimensions 2.4 dam by 16m find the number of tiles required

Answer 1

$\huge\mathbb{SOLUTION:-}$

Given :-

• Side of square tiles 40cm

• Dimension of hall =2.4dam and 16cm

Conver all the dimensions of room in cm

• 1dam=1000cm
• 2.4×1000=2400cm

And 16m to cm

• 1m=100cm
• 16m×100= 1600cm

• So The dimensions of hall is 2400cm and 1600cm

$\bf\underline{\purple{According\:to\: Question:-}}$

• Now first find the area of hall

• Area of rectangle=Length ×Breadth

$\tt Area \:of\:hall =2400cm\times 1600cm\\ \\ \tt\rightarrow Area\:of\:hall =3840000cm{}^{2}$

• $\tt Area\:of\:hall=3840000cm{}^{2}$

• Now find the area of square tiles

• Area of square =side×side

$\tt Area\:of\:tiles=40cm\times 40cm\\ \\ \tt\rightarrow Area\:if\:tiles=1600cm{}^{2}$

• The number of tiles required :-

$\sf\leadsto tiles\: required= \frac{Area\:of\:hall}{Area\:of\:tiles}\\ \\ \tt\implies\cancel {\frac{3840000}{1600}}\\ \\ \tt\Rightarrow Tiles\: required=2400$

• The number of tiles required for hall is 2400

#BAL

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Answer 2

$\underline \mathbb{SOLUTION}$

$\underline \mathbb{GIVEN}$

Side of square tile = 40cm

Dimension af hall = 2.4 dam and 16cm

CONVERSION TO CM:

1 dam = 1000 cm

2.4 × 1000 = 2400 cm

16 m in cm,

1m = 100 cm

16m × 100 = 1600 cm

$\underline \mathbb{HENCE}$

》DIMENSIONS OF HALL IS 2400cm and 1600cm

$\underline \mathbb{ATQ}$

NOW,

FIND THE AREA OF HALL:

$= > area \: of \: rectangle = l \times b$

$= > area \: of \: hall = 2400cm \: \times 1600cm$

$= > area = 3840000 {cm}^{2}$

NOW,

FIND THE AREA OF SQUARE TILES

$= > area \: of \: square = side \times side$

$= > area \: of \: tile = 40cm \times40cm$

$= > area = 1600 {cm}^{2}$

$\underline \mathbb{HENCE}$

》NO.OF TILES REQUIRED

$tiles \: required = \frac{area \: of \: hall}{area \: of \: tile}$

$= \frac{3840000}{1600}$

$= > 2400$

》TILES REQUIRED=2400

_______________________________________

#BAL

#Answerwithquality