Math, asked by sutheeshkrish1003, 6 months ago

Sura, a strongly distilledalcoholic drink was use in
ancient India as an anaesthetic by surgeons. A 15
litres cask initially contains pure Sura up to the brim.
The Sura is diluted by removing 5 litres and
replacing that quantity with water. If Sura is diluted
twice, what is the ration of Sura to water in the
cask? a.2:1 b.1:1 c.1:2 d.4:5​

Answers

Answered by student78623
3

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Answered by swethassynergy
1

The ration of Sura to water in the cask is 4:5 and option (d) is correct.

Step-by-step explanation:

Given:

15 liters cask initially contains pure Sura up to the brim.

The Sura is diluted by removing 5 litres and replacing that quantity with water.

Sura is diluted twice.

To Find:

The ration of Sura to water in the cask.

Solution:

As given,15 liters cask initially contains pure Sura up to the brim.

Sura =15 liters    and water=0 liters

As given,the Sura is diluted by removing 5 litres replacing that quantity with water.

Sura removed=5 liters

Sura remaining=10 liters

Water added=5 liters

Sura :Water =10:5=2:1

As given,Sura is diluted twice.

Solution removed= 5 liters

Amount of Sura in solution removed =5\times\frac{2}{3} =\frac{10}{3}

Amount of water in solution removed =5\times\frac{1}{3} =\frac{5}{3}

Sura remaining =10-\frac{10}{3}=\frac{30-10}{3} \\

                                               =\frac{20}{3}

Water remaining =5-\frac{5}{3} +5=\frac{25}{3}

Sura :water  =20:25=4:5

Thus,the ration of Sura to water in the cask is 4:5 and option (d) is correct.

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