Question

Surd:√2÷√48-√8-√27
Trig functions:

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{2} }{ \sqrt{48} } - \sqrt{8} - \sqrt{27}$

$\frac{ \sqrt{2} }{ \sqrt{2 \times 6 \times 4} } - \sqrt{2 \times 2 \times 2} - \sqrt{3 \times 3 \times 3}$

$\frac{1}{2 \sqrt{6} } - 2 \sqrt{2} - 3 \sqrt{3}$

$\frac{1 -4 \sqrt{12} - 6 \sqrt{18} }{2 \sqrt{6} }$

$\frac{1 - 8 \sqrt{3} - 18 \sqrt{2} }{2 \sqrt{6} }$

here is your answer