Surendra has some money with him he gave 40% of it to his son and 25% of the remaining to his daughter if 7200 are still left with him find the amount of money he had
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Let the initial amount with Mr.jones be Rs.x then,
Money given to wife= Rs.(40/100)x=Rs.2x/5.
Balance=Rs(x-(2x/5)=Rs.3x/5.
Money given to 3 sons= Rs(3X((20/200) X (3x/5)) = Rs.9x/5.
Balance = Rs.((3x/5) – (9x/25))=Rs.6x/25.
Amount deposited in bank= Rs(1/2 X 6x/25)=Rs.3x/25.
Therefore 3x/25=12000
x= ((12000 x 35)/3)=100000
So Mr.Jones initially had Rs.1,00,000 with him.
Short-cut Method :
Let the initial amount with Mr.Jones be Rs.x
Then,(1/2)[100-(3*20)]% of x=12000
=> (1/2)*(40/100)*(60/100)*x=12000
x=((12000*25)/3)=100000
Money given to wife= Rs.(40/100)x=Rs.2x/5.
Balance=Rs(x-(2x/5)=Rs.3x/5.
Money given to 3 sons= Rs(3X((20/200) X (3x/5)) = Rs.9x/5.
Balance = Rs.((3x/5) – (9x/25))=Rs.6x/25.
Amount deposited in bank= Rs(1/2 X 6x/25)=Rs.3x/25.
Therefore 3x/25=12000
x= ((12000 x 35)/3)=100000
So Mr.Jones initially had Rs.1,00,000 with him.
Short-cut Method :
Let the initial amount with Mr.Jones be Rs.x
Then,(1/2)[100-(3*20)]% of x=12000
=> (1/2)*(40/100)*(60/100)*x=12000
x=((12000*25)/3)=100000
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