Math, asked by cavin5313, 11 months ago

Suresh and ramesh can do a work in 45 days and 40 days respectively. They began the work together, but suresh left after some time, and ramesh finished the remaining work in 23 days. After how many days did suresh leave

Answers

Answered by MavisRee
0

Answer:

Thus, Suresh left after 9 days

Step-by-step explanation:

Suresh can complete work in 45 days

Thus, Suresh's 1 day work =\frac{1}{45}

Also, Ramesh can complete work in 40 days

Thus, Ramesh's 1 day work =\frac{1}{40}

Total work is LCM of 45 and 40 \hspace{0.1cm}=360\hspace{0.1cm}parts

Suresh's 1 day work =\frac{360}{45}\hspace{0.1cm}=8\hspace{0.1cm}parts

Ramesh's 1 day work =\frac{360}{40}\hspace{0.1cm}=9\hspace{0.1cm}parts

(Suresh + Ramesh)'s 1 day work =\hspace{0.1cm}8 + 9 = \hspace{0.1cm}17\hspace{0.1cm}parts

Now, Given that Suresh left after some time, and remaining is completed by Ramesh in 23 days

Thus, work completed by Ramesh in 23 days =\hspace{0.1cm}23 \times 9 = \hspace{0.1cm}207\hspace{0.1cm}parts

Therefore, Remaining work is completed by both Suresh and Ramesh together.

Now, remaining work =\hspace{0.1cm}360 - 207 = 153\hspace{0.1cm}parts

We know,

(Suresh + Ramesh) completes 17 parts in 1 day

(Suresh + Ramesh) completes 153 parts in \frac{153}{17}\hspace{0.1cm}=\hspace{0.1cm}9\hspace{0.1cm}days

Thus, Suresh left after 9 days

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