Suresh can finish piece of work by himself in 42 days.Mahesh who is 1/5 more efiicient than suresh requires x days
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No of days taken by Suresh to finish the work=42.
So part of work done by Suresh in one day =1/42.
Since Mahesh is 1/5 times more efficient as Suresh,part of work done by Mahesh in 1 day =1/42 + (1/5)×(1/42). = (1/42) + (1/210) =6/210=1/35.
So Mahesh can finish the work in 35 days.
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So part of work done by Suresh in one day =1/42.
Since Mahesh is 1/5 times more efficient as Suresh,part of work done by Mahesh in 1 day =1/42 + (1/5)×(1/42). = (1/42) + (1/210) =6/210=1/35.
So Mahesh can finish the work in 35 days.
Hope this is helpful to you..
Mark as brainlist
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