Question

suresh deposited rs.1250 in his saving bank account . Find the compound interest earned by him after 3 years if the rate is 5% per annum and the interest is payable annually.
​

Answer 1

Answer:

570

Step-by-step explanation:

Answer 2

$\bigstar$ GIVEN :-

• P(principal) = ₹1,250.
• R(rate) = 5% p.a.
• T(time) = 3years.

$\bigstar$ TO FIND :-

• The compound interest to added (payable) after 3 years.

$\bigstar$ SOLUTION :-

By using the formula of C. I.

$\bf \dashrightarrow a \: = { p(1 + \frac{r}{100} )}^{n} \\ \bf \: \dashrightarrow \: a \: = 1250 \times ( { 1 + \frac{ \cancel{5}}{ \cancel{100}}) }^{3} \\ \bf \: \dashrightarrow \: a \: = 1250 \times (1 + { \frac{1}{20}) }^{3} \\ \bf \: \dashrightarrow \: a = 1250 \times( { \frac{21}{20}) }^{3} \\ \bf \dashrightarrow \: a = 125 \cancel0 \times \frac{21}{20} \times \frac{21}{2 \cancel0} \times \frac{21}{20} \\ \bf \dashrightarrow \:{ \fcolorbox{orange}{pink}{ a = ₹1447.031}}$

$\bf \therefore \: c.i. = amount + principlal \\ \bf\dashrightarrow \: c.i. = 1447.031 + 1250 \\ \bf \dashrightarrow \: c.i. = { \fcolorbox{blue}{lightgreen}{₹269.031 \sf \: approx.}}$

✯ ADDITIONAL INFO ✯

✧C. I = A + PRINCIPAL

✧AMOUNT = P×(1+r/100)^n.

✧S. I = p × r × t/100.