Question

suresh has 4pencils and 2 eraseas he wants to tajes 1 pencil and eraser for the examination can we find the number if ways in which he can be select a pencil and eraser ​

Answer 1

there are total 8 ways Suresh can select a pencil and eraser ​ if suresh has 4pencils and 2 erasers

Step-by-step explanation:

suresh has 4pencils and 2 erasers

Suresh wants to use 1 pencil and eraser for the examination

the number of ways in which he can be select a pencil and eraser

= number of ways he can select pencil  * number of Ways he can select Eraser

= ⁴C₁ * ²C₁

= 4 * 2

= 8

there are total 8 ways Suresh can select a pencil and eraser ​ if suresh has 4pencils and 2 erasers

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Answer 2

Answer:

The number of ways to select a pencil and a eraser is 8 ways .

Step-by-step explanation:

Given as :

Number of pencil does Suresh has = 4 pencils

Number of eraser does Suresh has = 2 eraser

Again

Suresh want to gice 1 pencil and 1 eraser to Tajes

Let The number of ways to select a pencil and a eraser = n ways

According to question

Number of ways = $_{1}^{4}\textrm{C}$  ×  $_{1}^{2}\textrm{C}$

Or, n = $\dfrac{\angle 4}{\angle 1\times \angle 3}$  × $\dfrac{\angle 2}{\angle 1\times \angle 1}$

Or, n = $\dfrac{4\times \angle 3}{\angle 1\times \angle 3}$  × $\dfrac{2\times \angle 1}{\angle 1\times \angle 1}$            ( from factorial property )

∴   n = 4 × 2

i.e  n = 8

So, The number of ways to select a pencil and a eraser = n = 8 ways

Hence, The number of ways to select a pencil and a eraser is 8 ways . Answer