Suresh has a field in a triangular form, whose sides are 21 meter, 29 meter, and 30 meter. He wants to donate 1/4th area of his field to a blind school. Suggest him how to cut his field so that he can give accurate area to the blind school. Also prove it. What values are depicted by suresh
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This field is of an irregular triangle. Since we have all the sides we can use heroes formulae to get the area.
Heroes formulae =(S(s-a) (s-b) (s-c)) ^1/2
S=(a+b+c)/2
Substituting the values :S =(21+29+30)/2=40
(40(40-21)(40-29)(40-30))^1/2=(40×19×11×10)^1/2=289.14m2
The area to be given out is:1/4×289.14m2
=72.28m2
Heroes formulae =(S(s-a) (s-b) (s-c)) ^1/2
S=(a+b+c)/2
Substituting the values :S =(21+29+30)/2=40
(40(40-21)(40-29)(40-30))^1/2=(40×19×11×10)^1/2=289.14m2
The area to be given out is:1/4×289.14m2
=72.28m2
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