Question

SURESH IS TWICE AS SEEMA .IF SIX YEARS IS SUBTRACT FROM SEEMA 'S AGE AND 4 YEARS ARE ADDED TO SUDESH AGE SURESH WILL BE 4 TIMES SEEMA 'S AGE. HOW OLD WERE THEY 3 YEARS AGO

Answer 1

Let Suresh be X and Seema be Y. 
Given X = 2Y and 4(Y-6) = X+4 
=> 4Y-24 = X+4 
=> 4Y-24 = 2Y+4 (since X = 2Y) 
=> 4Y-2Y = 4+24 
=> 2Y = 28 
=> Y = 28/2 
=> Y = 14 
Sub Y = 14 in X = 2Y 
=> X = 2*14 
=> X = 28 

Therefore at present Suresh age is 28 and Seema's age is 14 
Suresh's age was 25 and Seema's age was 14 three years ago.

Answer 2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.