Math, asked by 9501090503jatinder, 19 days ago

Suresh purchased 6kg 250g wheat, 3kg 50g sugar and 10kg 800g flour. find the weight of his purchases in kg.​

Answers

Answered by dayanidhisharma19
19

Answer:

The answer is 20.100kg

Step-by-step explanation:

Suresh purchased,

wheat= 6kg 250g = 6.250kg

sugar = 3kg 50g = 3.050kg

flour = 10kg 800g = 10.800kg

therefore the total weight = (6.250+3.050+10.800) kg

  = 20.100 kg

Answered by preeti353615
5

Answer:

If the Suresh purchased 6kg 250g wheat, 3kg 50g sugar and 10kg 800g flour, then the weight of his purchases in kg is 20. 100 kg .​

Step-by-step explanation:

Given: Suresh purchased

     6kg 250g wheat,

      3kg 50g sugar

and 10kg 800g flour.

Find: the weight of his purchases in kg.

First convert weight in kg and then add

6kg.250 g = 6.250 kg

3 kg 50 g= 3.050 kg

10 kg 800 g = 10.800 kg

(6kg 250g ) + ( 3kg 50g) +(10kg 800g)

= ( 6.250  + 3.050 +  10.800 )

= 20. 100 kg

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