Question

Suresh walks on a straight road from his home to market 3 km away. He stopped by a shop to buy a pen and returned back home. It took him 30 minutes to reach home. The average speed of Suresh was-

Answer 1

AnsWer :-

✏ Distance travelled by Suresh from home to market is 3 km.

✏ And return back to home from the market the distance travelled by him in this time is 3 km

✏Total time taken by the Suresh is 30 minutes.

✏ Now, we need make the units same. So, we have to convert the distance travelled by Suresh from km to m and time taken from minutes to seconds.

⍟ Total Distance ⍟

↠Total Distance = 3 km + 3 km

↠Total Distance = 6 km

↠Total Distance = 6 × 1000 m

↠Total Distance = 6,000 m

⍟ Total Time taken : ⍟

↠Total time taken = 30 min

↠Total time taken = 30 × 60 s

↠Total time taken = 1,800 s

✣ Average Speed : ✣

→ Average speed = Total distance/Total time

→ Average speed = 6,000/1,800

→ Average speed = 60/18

→ Average speed = 3.34 m/s

Answer 2

at first, he walks from home to market = 3 Km

and then he returns from market = 3 Km

total distance covered here is = 3 + 3 = 6 Km

returning from market to home... it took 30 minutes

so while going to market.. it took the same distance

= 30 min + 30 min

= 60 min

= 1 hour

Average speed = total distance/ total Time

= 6 km/ 1 hour

= 6 Km/hr.

if you want an answer in m/s .... then convert 6 km/h into m/s by multiplying 6 Km × 5/18..!!