Question

Suresh was running at the speed of 18mph Pune road parallel to rail track a train 200 m long overtook him in 10 second what must be the speed of the train​

Answer 1

Step-by-step explanation:

its good quition dear right answer

21×23=342

Answer 2

Answer:

The Speed of the train in this scenario is 38mph

Step-by-step explanation:

given in the question,

Suresh's speed = 18mph

Suresh is moving parallel to a rail track, with a train of 200m over took him.

time (t)=10 sec

speed of train (S)=?, let S=x mph

Here the keyword to this question us the speed of Suresh was overtook by a 200m train in 10 sec, that is nothing but the speed of the train

hence , we can use the concept of relative speed and apply the speed formula.

since it overtook, we can use the formula,

distance= speed * time

here we consider the relative speed of Suresh and train.

$200=(x-18)*10$

$x= 20+18$

x=38.

Speed of the train is 38mph