Question

Surface area and volume class 10 all formulas

Answer 1

CUBE:

C.S.A = 4a²

T.S.A = 6a²

Volume  = a³

CUBOID:

C.S.A = 2(lh+bh)

T.S.A = 2(lb+bh+hl)

Volume = lbh

CYLINDER:

C.S.A =  2πrh

T.S.A = 2πr(r+h)

Volume = 2πr²h

CONE:

C.S.A = πrl

T.S.A = πr(l+r)

Volume = ¹/₃πr²h

SPHERE:

T.S.A = 4πr²

Volume = ⁴/₃πr³

HEMISPHERE:

C.S.A = 2πr²

T.S.A = 3πr²

Volume = ²/₃πr³

FRUSTUM:

C.S.A = π(r+R)l

T.S.A = πl(r+R)+π(r²+R²)

Volume = ¹/₃π(r²+R²+rR)h

PLEASE MARK AS BRAINLIEST

Answer 2

All the formulas of the surface area and volume for class 10th are given below:

1) Cube

Curved surface area (CSA) of cube = 4a²

Total surface area (TSA) of cube = 6a²

Volume = a³ ( Note that all the sides of a cube are equal)

2) Cuboid

CSA = 2h(l + b)

TSA = 2 (lb + bh + hl)

Volume= lbh ( l, b, and h stands for length, breadth and height respectively)

3) Cone

CSA = πrl

TSA = πr(l+r)

Volume = 1/3πr²h ( r is the radius, h is the height and l is the slant height. l can be found using the formula l² = h²+r².)

4) Sphere

TSA = 4πr²

Volume = 4/3πr³ ( r is the radius of the sphere)

5) Hemisphere

CSA = 2πr²

TSA = 3πr²

Volume = 2/3πr³

6) Cylinder

CSA = 2πrh

TSA = 2πr(r+h)

Volume = 2πr²h ( r and h are the radius and height of the cylinder respectively.)

7) Frustum of a cone

CSA = πL(r+R)

TSA = πL(R+r) + π(R²+r²)

Volume = 1/3πHr²+R²+rR)

L² = H² + (R-r)²