Question

Surface area and volume formulas for frustum of a cone

Answer 1

━━━━━━━━━━━━━━━━━━━━━━━━━

$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\Large\fbox{\color{purple}{QUESTION}}$

SURFACE AREA VOLUME FORMULAS

━━━━━━━━━━━━━━━━━━━━━━━━━

$\Large\fbox{\color{purple}{ SOLUTION }}$

$\Large\mathcal\pink{FRUSTUM}$

$\implies \: tsa = \pi \: l(r1 + r2) + \pi \: {r1}^{2} + \pi {r2}^{2}$

$\implies volume = \frac{1}{3}\pi \: h( {r1}^{2} + r1.r2 + {r2}^{2} )$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\bf\Large\red{ THANKS \: FOR \: YOUR}$

$\bf\Large\red{ QUESTION \: HOPE \: IT }$

$\bf\Large\red{ HELPS }$

$\Large\mathcal\green{FOLLOW \: ME}$

━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 2

Answer:

$\huge\boxed{\fcolorbox{Blue}{White}{Your's Answer}}$

$<font color= "Red"> Frustum</p><p>Curved Surface Area = π(r 1 + r 2 )l.</p><p>Total Surface Area =π(r 1 + r 2 )l + πr 1 2 + πr 2 2</p><p>Volume = 1/3 πh (r 1 2 + r 2 2 + r 1 r 2 )$

$<marquee behaviour-move><font color="orange"><h1>#itzcutiepie </h1></marquee>$