surface area of a cuboid whose Length breadth and height are 10 cm 8 cm and 8 cm he is
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length = 10 cm
breadth = 8 cm
height = 8 cm
TSA = 2(LB + BH + HL)
= 2× (10×8+8×8+8×10)
=2×(80+64+80)
= 2× 224
=448 Cm^2
breadth = 8 cm
height = 8 cm
TSA = 2(LB + BH + HL)
= 2× (10×8+8×8+8×10)
=2×(80+64+80)
= 2× 224
=448 Cm^2
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