Physics, asked by starboyyy8081, 9 months ago

Surface area of solid cylinder of radius 2.0cm and height acm is equal to 1.5*104mm2. Here a refers

Answers

Answered by diwanruhi12
0

Answer:

a = - \frac{4127}{4400}

Explanation:

Surface Area of cylinder

= 2\pi r (r + h)

Where 'r' = radius of the base circles and 'h' = height of cylinder

Putting the values, we get

= 2\pi 2 (2 + a) = 1.56

= 4\pi (2 + a) = 1.56

= 8\pi + 8\pi a = 1.56

= 8\pi (1 + a) = 1.56

= \frac{176}{7}  (1 + a) = 1.56

= 1 + a = \frac{156}{100} *\frac{7}{176}

= 1 + a = \frac{39}{100} *\frac{7}{44}

= 1 + a = \frac{273}{4400}

= a = \frac{273}{4400} - 1

= a = - \frac{4127}{4400}

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