Surface area
of spherical Shell= 4pi (R²- r^2)
where R= external radius, r= internal
radius:
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Answer:
For a thin uniformly charged spherical shell, the field points outside the shell at a distance x from the centre is
E=
4πε
0
1
x
2
Q
If the radius of the sphere is R,Q=σ4πR
2
∴E=
4πε
0
1
x
2
σ4πR
2
=
ε
0
x
2
σR
2
This is inversely proportional to square of the distance from the centre. It is as if the whole charge is concentrated at the centre
Step-by-step explanation:
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