Question

SURFACE AREAS AND VOLUMES
239
Example-11. A hemispherical bowl is made up of stone whose thickness is 5 cm. If the inner
radius is 35 cm, find the total surface area of the bowl.
Solution : Let R be outer radius and 'r'be inner radius Thickness of ring=5 cm
ne som
he
.: R= (r + 5) cm = (35 + 5) cm = 40 cm
Total Surface Area = CSA of outer hemisphere+CSA of inner hemisphere + area of the ring.
2TR2 + 27trº + T(R? -P)
T(2R² +21² + R² - (²)
35 cm.
5 cm.
22
(3R2
22
(3x 40° +352)cm​

Answer 1

Answer:

14,083

Step-by-step explanation:

Let R be outer radius and 'r'be inner radius Thickness of ring=5 cm

ne som

he

.: R= (r + 5) cm = (35 + 5) cm = 40 cm

Total Surface Area = CSA of outer hemisphere+CSA of inner hemisphere + area of the ring.

2TR2 + 27trº + T(R? -P)

T(2R² +21² + R² - (²)

35 cm.

5 cm.

22

(3R2

22

(3x 40° +352)cm